language agnostic - Regex match all the words outside quotation marks? -

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Is it possible to match text outside the quotation marks by using the standard regex parser? I have seen this answer, but it is done using PCR:

This is not a pure solution due to using Perl. I know that it uses the programming language It can also be solved by using, but this idea is to use the pure Regedx Parser.

I did something like that, but it is not working properly 

  [^] (? = (?: ([']] + ( . *? \ 1)) | ([^ ''] * $))

Thank you in advance.

UPD1 : This idea is to match any type of text to quotation marks; the solution should not depend on the input. 

  & lt; Yourtext & gt; (? = =? (?: [^ "] *" [^ "] *") * [^ "] * $)

Yes, you can use it positively But it assumes that you have balanced " and there is no stray " somewhere lying. See the demo.


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