string - perl match whole word only with array list -

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I should be able to match a user in the list of users, but only one exact match In the sample code given below:
- If there is "information" in Strucer then there is a match and it is good.
- If there is "theinfo" in Strucer, or "Infstrift" is a match and it is not good.
I can not use the \ b modifier because the variable does not have only usernames, spaces, or word boundaries. 

  #! / Usr / bin / perl $ strUser = "theinfo"; $ StrUsers = "(alpha | info | omega)"; If ($ strUser = ~ / $ strUsers /) {print "match \ n"; } Exit (0); Use borders within your regex  ^  and    
 
 \ Z : 
 
  If ($ strUser = ~ / ^ $ strUsers \ z /) {  
 Note, because you may be able to read literal strings Want to work with, I  quotemeta :  
  #! Using / usr / bin / perl, I will do more to build my regex; Use warnings; My $ strUser = "theinfo"; My @ user = qw (alpha info omega); My $ list_users_re = join '|', map {quotemeta} @user; If ($ strUser = ~ / ^ ($ list_users_re) \ z /) {print "match \ n"; } Exit (0);  
 
 However, since the search for exact matches, one easy solution is to use only one hash: 
 
  my @users = qw (alpha Information omega); My% is_user = map {$ _ = & gt; 1} @ User; If ($ is_user {$ strUser}) {print "match \ n"; }  
 
 Finally, always include and in every Perl script.

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