c# - Check if file exists on FTP - Don't know the name of the file -

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I get a file on the FTP server, the name of the file is dynamically generated I have a program on the server I am trying to write a program to see whether or not I have. 

  string userName = Dts.Variables ["User :: SFTPUsername"]. Value.ToString (); String Password = Dts.Variables ["User: SFTPPassword"]. Value.ToString (); ** string filename = Dts.Variables ["User :: FilePattern"]. Value.ToString (); ** string ftpURL = String.Format ("ftp: //11.11.11/upload/ {0}", filename); WebClient Request = New Webclient (); request. Credential = new network credentials (username, password); FtpWebRequest ftpRequest = (FtpWebRequest) WebRequest.Create (ftpURL); FtpRequest.Method = WebRequestMethods.Ftp.GetFileSize; FtpRequest.Credentials = New network credentials (username, password); (FtpWebResponse ftpResponse = (FtpWebResponse) using ftpRequest.GetResponse ()) {byte [] newFileData = request.DownloadData (ftpURL.ToString ()); String fileString = System.Text.Encoding.UTF8.GetString (newFileData); String strxist = string.format ("exist"); MessageBox.Show (strexist); Dts.Variables ["User :: FileExists"]. Value = true; }

This only works well when I specify "filename". Anyway I can search a wildcard ("* .txt") or search file upload folder Is in or not?

Any help appreciated !!

You can list filenames from FTP . Like below ... 

  FtpWebRequest request = (FtpWebRequest) WebRequest.Create (ftpURL); Request.Method = WebRequestMethods.Ftp.List directory; FtpWebResponse response = (FtpWebResponse) request.GetResponse (); (StreamRisstream = Feedback.GetrespanSstream ()) using {StreamReader Reader = New StreamMaster (respStream); // Read the name of each file for response (string fname = reader.ReadLine (); fname! = Null; fname = reader.ReadLine ()) {// Add file name to a list}}  < / Pre> 
 If the list count is 0 then no file is available, apart from this you will get the name of each file in a list from a single request. Repeat list values ​​using 
 
  foreach loop . And make the above code as a method 
 
  Note:  Pass the file name in this file. 
 
 You can also ensure that the special filename exists or not in the list. 
 
  Note:   file name

on url


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