regex - How to escape the second capture group the first time in javascript regular expression -

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This would be useful if someone could recommend a way to avoid another capture group for the first time. The expression is as follows: 

  (\ d) (? = (\ D {3}) (\ d {2}) + (?! \ D))

I want to leave the second capture group (\ d {2}) for the first time and evaluate this group (\ d {3}) just one time.

This idea is to find the position of the number. Now, 1000000000 as of 1,00,00,00000 is being evaluated, I want it to be 1,00,00,00,000.

It looks like this should work for you: 

  "1000000000" .replace (/ \ d (? = (?: \ D {2}) * \ d {3} (?! \ D)) / g, "$

I removed all unnecessary capturing groups, and instead of capturing \ d, use $ & amp; to reference the main match .


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