java - What type is bit shift operator output? -

-

मेरे पास निम्न कोड है 

  सार्वजनिक स्थिर शून्य मुख्य (स्ट्रिंग [] args) { // 32 बिट पूर्णांक int का पता लगाएं = a = 0x6348987C; एक = एक & gt; & gt; 31; इंट एक = ए और 1; यदि (एक == 0) {System.out.println ("सकारात्मक"); } Else {System.out.println ("नकारात्मक"); }}

यदि मैं के साथ तुलनात्मक रेखा को बदलता हूं (यदि एक (& amp; 1 == 0) संकलन ऑपरेटर के साथ विफल रहता है & amp; इंटेल, बूलियन पर लागू नहीं किया जा सकता है, मुझे आश्चर्य है कि बदलाव ऑपरेटर के परिणामस्वरूप प्रकार क्या है I

== समानता ऑपरेटर ऑपरेटर के मामले में bitwise और operator से पहले होता है प्राथमिकता (देखें) आपको बाद के अग्रसारण को बनाने के लिए कोष्ठकों को रखना चाहिए: 

  यदि ((ए और amp; 1) == 0) {  
 ध्यान दें कि का परिणाम  a & amp; 1  मूल कोड ( int ) में एक ही प्रकार का  एक  है।

Comments

Post a Comment

Popular posts from this blog

mysql - How to enter php data into a html multiple select box -

-
I am working on a page that will create a team. I just want to create a selection box which will list all the users of all the users. After that, the user can select more than one friend (i.e. 5) and can send the request to these 5 people to join the team but I am having problems I did this: Select $ sql = "Select i. *, Join * Connect with M * m.id = i.clique_id where adder_id =: id"; $ Stmt = $ db- & gt; Query ($ sql, array ('id' = & gt; $ _SESSION ['id'])); While ($ record = $ stmt-> fetch ()) {$ surname = $ record ['surname']; } and this: & lt; Select multiple = "true" name = "category" well id = "category" name = "category" category = "" & gt; & Lt; Option value = "& lt ;? php echo $ surname ;? & gt;" & Gt; & Lt ;? Php ek $ nickname; ? & Gt; & Lt; / Options & gt; & Lt; / Select & gt; But only a friend's nickname...
Read more

java - Can't add JTree to JPanel of a JInternalFrame -

-
Image
There are two panels in my JInternalframe. I want to add TopPanel to Jtree to nominate another. But I can not add Jaitari to the top of the panel. Please help me in this piece of code: DefaultMutableTreeNode root = new DefaultMutableTreeNode ("deck"); DefaultMutableTreeNode Item Clubs = New DefaultMutableTreeNode ("Club"); AddAllCard (itemClubs); Root.add (itemClubs); DefaultMutableTreeNode item = New DefaultMutableTreeNode ("Diamonds"); AddAllCard (itemDiamonds); Root.add (itemDiamonds); DefaultMutableTreeNode Itemspads = New DefaultMutableTreeNode ("Spades"); AddAllCard (itemSpades); Root.add (itemSpades); DefaultMutableTreeNode item increases = new DefaultMutableTreeNode ("heart"); AddAllCard (itemHearts); Root.add (itemHearts); Default Trimodel Tree Model = New DefaultTreeModel (Route); Tree = new jetty (tree modal); ScrollPane = new JScrollPane (tree); // scrollPane.setViewportView (tree); . ScrollPane.getViewport () add (tr...
Read more

c++ - Cassandra datastax cpp driver - avoiding unnecessary copies -

-
I use the following method to create my insert statement for Cassandra (using datastax cpp driver) : ssStmt1 & lt; & Lt; "Insert some table (...) value (....)" string sStatement1 = ssStmt1.str (); Castestring cass1 = cass_string_init (sStatement1.c_str ()); CassStatement * pStmt1 = cass_statement_new (cass1, 0); I have also tried the following: CassString cass1 = cass_string_init ("Enter some table (id, date, c) value (? ,?,?); "); CassStatement * pStmt1 = cass_statement_new (cass1, 3); Cass_statement_bind_uuid (pStmt1, 0, uuidKey); Cass_statement_bind_int64 (PSTMT1, 1, timestamp); Cass_statement_bind_string (pStmt1, 2, sSomething); The first pattern works with mixed keys, the second is not. The key has a timestamp and a UUID. Timestamp is one of two errors in the field (based on the used bond statement). If bound in this way: cass_statement_bind_int64_by_name (pStmt1, "date", timestamp); I get the following error: Inva...
Read more