Java regex (to me) unexpected behaviour -

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इस सवाल का पहले से ही एक उत्तर है: < / P>

  • 1 उत्तर

मेरे पास निम्न जावा कोड है : 

  पैटर्न p = Pattern.compile ("#। *,", पैटर्न। DOTALL); Matcher m = p.matcher ("# $ 0: = डिफ़ॉल्ट के साथ युक्ति (एक्स, वाई) {{\ \ system.out.println (x + y); \ n}};"); जबकि (m.find ()) {System.out.println ("मिला:" + m.group () + "।"); }

और मुझे मिल रहा है: 

  मिला: # $ 0: = डिफ़ॉल्ट के साथ युक्ति (एक्स, वाई) {{System.out.println (x + वाई); }} ;.

वही जो मुझे चाहिए लेकिन उपरोक्त पैटर्न से मुझे यह उम्मीद है कि यह # और पहले सेमीकोलन के बीच कुछ भी मैच करे, न कि पिछले एक I.e., मैं इसे $ 0: = Spec (x, y) को डिफ़ॉल्ट {{System.out.println (x + y) से मिलान करने की अपेक्षा करता हूं; । यह कैसे पिछले सेमीकोलन से मेल खाता है 

  पैटर्न p = Pattern.compile (" #। * ?; ", पैटर्न। DOTALL);  *   *   के बाद  *  जोड़कर अपना प्रतिमान न लालच करें
अधिकतम कर सकते हैं।


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