scala - how to create a new play project with sbt -

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हाय मैं sbt (scala build tool) के साथ एक नाटक प्रोजेक्ट बनाने का प्रयास कर रहा हूं I

अनुभाग के तहत "स्थापित किए बिना एक नया एप्लिकेशन बनाएं" मैंने एक ही अनुदेश का अनुकरण किया है

यह मेरा प्रोजेक्ट / बिल्ड.scala फ़ाइल है 

  import sbt._ import Keys ._ आयात PlayProject._ ऑब्जेक्ट ApplicationBuild विस्तार बनाता है {val appName = "playsbtproj" val appVersion = "1.0" val मुख्य = PlayProject (appName, appVersion, app निर्भरता, mainLang = SCALA)}

और यह मेरा प्रोजेक्ट / प्लगइन्स.sbt फ़ाइल है 

  रिज़र्वर्स + = "टाइपराफे रिपॉजिटरी" "http://repo.typesafe.com/typesafe/releases/" // पर Play sbt का उपयोग करें प्ले प्रोजेक्ट्स के लिए प्लगइन addSbtPlugin ("com.typesafe.play"% "sbt-plugin"% "2.2.3")

जब मैं अपनी परियोजनाओं में एसबीटी टाइप करता हूँ तो एसबीटी मुझे निम्नलिखित एरोर्स देता है 

  [info] / opt / programs / play / playsbtproj / proje से परियोजना परिभाषा लोड हो रही है सीटी [info] 1 स्काटल स्रोत को /opt/programs/play/playsbtproj/project/target/scala-2.10/sbt-0.13/ वर्ग में संकलित करना ... [त्रुटि] / ऑप्ट / प्रोग्राम / प्ले / नाटकोंबेटप्रोजे / प्रोजेक्ट / बिल्ड। स्काला: 3: नहीं मिला: ऑब्जेक्ट PlayProject [त्रुटि] PlayProject._ [error] ^ [error] /opt/programs/play/playsbtproj/project/Build.scala:8: नहीं मिला: मूल्य PlayProject [त्रुटि] val मुख्य = PlayProject [त्रुटि] दो त्रुटियां मिली [त्रुटि] (संकलन: संकलन) संकलन विफल परियोजना लोड करने में असफल रहा: (आर) एट्र्री, (क्यू) यूआईटी, (एल) एस्ट, या (आई) गठबंधन? कृपया इस समस्या को कैसे ठीक करें

पाठ "आइटमप्रॉप =" पाठ ">

चयनित संस्करण के लिए का उपयोग करें (आपके मामले में 2.2.3)।

आउट-ऑफ-द-बॉक्स काम करता है


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