python - Split a string by backslash -

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I am trying to divide a path to get the name of the file, in the last part of the string, and I I am working with a problem I can not solve with:

My string: to = 'c: \ user \ desktop \ test \ excel_ports \ 1837.xlsx'

I did this: 

  & gt; & Gt; & Gt; Te.split ('\\') ['C:', 'User', 'Desktop', 'Test', 'Excel_Reports xx837.xlsx'] & gt; & Gt; & Gt; Te.split ('\\') [-] 'Excel_Reports \ x01837.xlsx'

I do not know what is the problem with \ 0 or \ number .... Is this a special Python character?

Here's what I want: 

  ['c:', 'user', 'desktop', 'exam', 'excel_ports', '1837.xlsx' ]

But I can not do this at all.

PD: There is no valid solution such as file_name = te [-5: -1] because the name of the excel file can be different at any time, although the usual number. Edit None, how to find "Load Excel") in the Oslistdir (folder): if f.endswith (".xlsx"): te = os.path.join (str (folder), str (f) )) #bla, bla, bla, ...... Thanks for all the replies and comments, they told me in the right direction. However, I resolved this issue by Rebecca NG this line: 

  Code> te = os.path.join (str (folder), str (f))

For this one: 

  te = os Path.join (folder, f)

And then, it works: 

  te.split ('\\') [- 1] .split ('.') [0]

returns the file name (number) without extension xlsx

You need to make text te for a raw string

Rw> & gt; & Gt; & Gt; Te = r'C: \ Users \ Desktop \ test \ Excel_Reports \ 1837.xlsx '& gt; & Gt; & Gt; Import OS & gt; & Gt; & Gt; Te.split ("\\") # OS can not use path.sep because my rip is on linux ['c:', 'user', 'desktop', 'test', 'excel_ports',' 1837 Xlsx ']

This dragon is due to syntax for literal strings \ g , \ n , \ t < / Code> etc. will also create problems. Do not need to avoid other slashes, because this character is not a valid escape sequence - but it is confused as hell. Better to use raw string syntax

If you are getting te from a source file other than an example, for example an ini file or database (as you would like ), You can not even see this problem


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