mysql - How to display same picture on new php page when clicked on the picture? -

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This is my code to show pictures from MySQL. 

  echo & lt; Table & gt; '; Echo '& lt; Tr & gt; '; Echo '& lt; Td> & Lt; A href = "imagedisplay.php" & gt; & Lt; Img src = "galleryshow.php? Id = '. $ Line [' id '].' 'Width =" 300 "height =" 250 "/> gt; & lt; / td & gt;'; write; & lt; ; Li & gt; Species: '. $ Line [' Species]]. '& Lt; / li & gt; & lt; li & gt; Age:'. $ Line ['age']. '& Lt; / Li & gt; & lt; li & gt; Gender: '$ line [' gender '].' & Lt; / li & gt; & lt; li & gt; Date: '$ line [' date '].' & Lt; / li & gt; & lt; li & gt; Time: & lt; / li & gt; & lt; li & gt; Location: '. $ Line [' location '].' & Lt; / li & gt; & lt; li & gt; Note: '. $ Row [' comment '].' & Lt; / li & gt; & lt; / td & gt; '; echo & lt; / tr & gt;'; echo '& lt; / table & gt;';
< P> I want to display the same image on imagedisplay.php .

This is not a lot of answers, because this is not a question:

You have to give your $ line ['id'] as a parameter imagedisplay.php Using something like: GET will look something like this:

echo & lt; td & gt; & lt; a href = "imagedisplay.php? Rowid = '. $ Row ['id'] "& Gt; & lt; img src =" galleryshow.php? " Id = '. $ Line ['id']. '' Width = "300" height = "250" /> gt; & Lt; / A & gt; & Lt; / Td> ';

You have to select that variable in your imagedisplay.php code and then use it as you did here.


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